Find The Given Number is Armstrong in C - Working Code

#include<stdio.h>
#include<conio.h>
void main()
{
   int n, n1, rem, num=0;
   clrscr();
   printf("Enter a positive integer: ");
   scanf("%d", &n);
   n1=n;
   while(n1 != 0)
   {
      rem = n1%10;
      num+=rem*rem*rem;
      n1/=10;
   }
   if(num == n)
   printf("%d is an Armstrong number.",n);
   else
   printf("%d is not an Armstrong number.",n);
   getch();
}

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To Run Press Ctrl+f9

Output: